H : given_point a b (x :: t)
eq1 : nos = 0
IHimg' : given_point a b t -> false = true
Are these two hypothesises false?
What is given_point
, what is nos
?
given_point is function's name, nos a b :nat
If you manage to prove that given_point a b (x :: t) -> given_point a b t
yes there is a contradiction, otherwise no
Last updated: Oct 13 2024 at 01:02 UTC