max b (list_max l) <> 0 ->
b <= list_max (b :: l) ->
max b (list_max l) <= b -> False
Hi, Sara,
It lacks some information about your statement, for instance about the variables l
and b
(no quantifier nor hypothesis).
For instance, if I pose l := repeat 2 2
and b:=2
your statement is false.
Pierre
Last updated: Sep 26 2023 at 11:01 UTC