Is there a lemma in derive.v
stating the uniqueness of the differential of a differentiable function ? I can't find it.
Lemma diff_unique (V W : normedModType R) (f : V -> W)
(df : {linear V -> W}) x :
continuous df -> f \o shift x = cst (f x) + df +o_ (0 : V) id ->
'd f x = df :> (V -> W).
(I guess the equality in the end should have been swapped though)
So if I want to show that a function is derivable by providing its differential ad hoc, what should I do ? Meaning I want to prove derivable f a
, by showing it is differentiable with its differential being a certain linear map.
Am I right to undderstand that diff_unique
, and all the lemmas which depend on it, do not apply to complex analysis, because the norm on V
and W
needs to target a realDomainType
? Should everything be redefined for complex analysis ?
I guess that everything should indeed be generalized...
What do you mean by "generalized"? to any numFieldType
?
Sounds a bit weird. This seems to be as an oddity of "forgetting" that the norm is not real-valued.
I'm not sure I understand your remark
I did not noticed it before, but using case: (real_le0P (normr_real x))
instead of case: ler0P
|x| or
lerP |x| 0
in several lines of derive.v
should allow to generalize all the sections using a realFieldType
to using a numFieldType
. Do you see an obstacle or could I suggest a PR ?
So contrarily to what I said to you earlier @Assia Mahboubi , the norm is always real-valued on any numDomainType
.
Hi. Is there some result in the library that allows me to compare two functions knowing their derivative (and a common point). It seems that not that much has been proved in derive.v
Nevermind, the mean value theorem will do the job.
By the way, if I do a Check MVT
, it prints continuous f
instead of {within [a, b], continuous f}
.
Follow-up question: how can I prove {whithin [0, 1], continuous sin}
from continuous sin
?
Pierre-Yves Strub said:
Follow-up question: how can I prove
{whithin [0, 1], continuous sin}
fromcontinuous sin
?
Pierre-Yves Strub said:
By the way, if I do a
Check MVT
, it printscontinuous f
instead of{within [a, b], continuous f}
.
Indeed, that's an issue... https://github.com/math-comp/analysis/blob/82667438ee3f6e9b030a9654bd62e18b23d31b88/theories/topology.v#L5972-L5973 should be parsing only and complemented with a printing only notation that fetches the domain from the type of the subspace in the implicit arguments of continuous. CC @Zachary Stone what do you think?
Cyril Cohen said:
Pierre-Yves Strub said:
Follow-up question: how can I prove
{whithin [0, 1], continuous sin}
fromcontinuous sin
?
I finally understood that I had to Import numFieldNormedType.Exports
to be able to apply this lemma.
Isn't this module be exported by default?
I have a function that is derivable over an interval, I want to prove that it is continuous over that interval. I cannot find a way to prove it directly
Pierre-Yves Strub said:
Isn't this module be exported by default?
This module breaks forgetful inheritance, it should definitely be documented in the header of theories/normedtype.v
as "Import only locally and at your own risks" or something.
Pierre-Yves Strub said:
I have a function that is derivable over an interval, I want to prove that it is continuous over that interval. I cannot find a way to prove it directly
I've seen this lemma, but never managed to apply it.
I'll give more context later
Regarding the the proof of continuous sin -> {within [0,1], continuous sin}
, you should be able to combine continuous_subspaceT
and continuous_subspace_in
. It sounds like a making this a separate lemma would be useful.
Regarding the printing, I have been frustrated by this as well. You get goals like
continuous f -> continuous f
which is super misleading. I hacked around this with the pointwise vs. uniform convergence by introducing pointwise_fun
and uniform_fun
, but this solution is pretty poor. I'd love some help to improve the printing.
Lastly, regarding derivable on an interval
implies continuous on an interval
, I am not surprised that differentiable_continuous
doesn't work for free if it's using the wrong topologies. To be more helpful, I'd need to know exactly how derivable on an interval
is phrased in your setting.
Last updated: Oct 13 2024 at 01:02 UTC